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Subsequences
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Borg7
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PostPosted: Fri Nov 25, 2011 9:02 pm    Post subject: Subsequences Reply with quote

Be (X,d) a metric space and (x_n)_n€N a sequece in X. Prove: (x_n)_n€N converges when the subsequences (x_2n)_n€N, (x_2n+1)_n€N and (x_3n)_n€N converge.

Any ideas?
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aggsyb
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PostPosted: Fri Nov 25, 2011 9:34 pm    Post subject: Reply with quote

Yea stop trying to make yourself look so smart for ego. Your making yourself look gay
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Borg7
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PostPosted: Fri Nov 25, 2011 9:38 pm    Post subject: Reply with quote

Lol, I need to hand in the paper soon but idk how to solve this...it's prob pretty simple for some1 who's good at math
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Brokerstar
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PostPosted: Fri Nov 25, 2011 9:39 pm    Post subject: Reply with quote

Borg7 wrote:
Lol, I need to hand in the paper soon but idk how to solve this...it's prob pretty simple for some1 who's good at math


'good at math' or math genius?
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aggsyb
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PostPosted: Fri Nov 25, 2011 9:41 pm    Post subject: Reply with quote

I think the biggest problem though is that your still coming accross as gay, and its common knowledge that gay people are not liked and in some countries not tolerated. Dont go travelling
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Borg7
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PostPosted: Fri Nov 25, 2011 9:45 pm    Post subject: Reply with quote

Brokerstar wrote:

'good at math' or math genius?


Laughing
do you remember the sn of the mathematician guy on here?
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chesslw
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PostPosted: Sat Nov 26, 2011 11:33 am    Post subject: Reply with quote

I might be able to answer this, or at least give you a hint. It really depends how much you have "proved" so far.

But if you know that any subsequence of a convergent sequence converges to the same limit (or if not then use for all epsilon there exists N etc etc it isn't too hard), then consider:

X_6n which is a subsequence of X_2n and X_3n, therefore X_2n and X_3n converges to the same limit. Similarly X_6n+3 is a subsequence of X_2n+1 and X_3n, and so X_2n+1 and X_3n have the same limit.

Therefore all 3 sequences have the same limit, x say, so the whole sequence converges to the same limit.

Of course you should use formal notation, i.e. epsilon-N notation.

Hope that helps!

Edit- missed the v. important bolded part the first time...
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BetMagicMoney
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PostPosted: Sat Nov 26, 2011 11:44 am    Post subject: Reply with quote

feck knows, i like to think i know math but this is just some high level sh1t bro Razz
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aggsyb
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PostPosted: Sat Nov 26, 2011 12:05 pm    Post subject: Reply with quote

chesslw wrote:
I might be able to answer this, or at least give you a hint. It really depends how much you have "proved" so far.

But if you know that any subsequence of a convergent sequence converges to the same limit (or if not then use for all epsilon there exists N etc etc it isn't too hard), then consider:

X_6n which is a subsequence of X_2n and X_3n, therefore X_2n and X_3n converges to the same limit. Similarly X_6n+3 is a subsequence of X_2n+1 and X_3n, and so X_2n+1 and X_3n have the same limit.

Therefore all 3 sequences have the same limit, x say, so the whole sequence converges to the same limit.

Of course you should use formal notation, i.e. epsilon-N notation.

Hope that helps!

Edit- missed the v. important bolded part the first time...


So hold on a sec, what your saying is it has NOTHING to do with being like and or actually being gay?
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U Cook Socks
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PostPosted: Sat Nov 26, 2011 12:16 pm    Post subject: Reply with quote

aggsyb wrote:
chesslw wrote:
I might be able to answer this, or at least give you a hint. It really depends how much you have "proved" so far.

But if you know that any subsequence of a convergent sequence converges to the same limit (or if not then use for all epsilon there exists N etc etc it isn't too hard), then consider:

X_6n which is a subsequence of X_2n and X_3n, therefore X_2n and X_3n converges to the same limit. Similarly X_6n+3 is a subsequence of X_2n+1 and X_3n, and so X_2n+1 and X_3n have the same limit.

Therefore all 3 sequences have the same limit, x say, so the whole sequence converges to the same limit.

Of course you should use formal notation, i.e. epsilon-N notation.

Hope that helps!

Edit- missed the v. important bolded part the first time...


So hold on a sec, what your saying is it has NOTHING to do with being like and or actually being gay?


I'm fairly certain it does to be honest.
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